Optimal. Leaf size=90 \[ \frac{\left (a+b \tan ^{-1}\left (c x^2\right )\right )^2}{4 c^2}-\frac{a b x^2}{2 c}+\frac{1}{4} x^4 \left (a+b \tan ^{-1}\left (c x^2\right )\right )^2+\frac{b^2 \log \left (c^2 x^4+1\right )}{4 c^2}-\frac{b^2 x^2 \tan ^{-1}\left (c x^2\right )}{2 c} \]
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Rubi [C] time = 1.04173, antiderivative size = 612, normalized size of antiderivative = 6.8, number of steps used = 44, number of rules used = 16, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 1., Rules used = {5035, 2454, 2401, 2389, 2296, 2295, 2390, 2305, 2304, 2395, 43, 2439, 2416, 2394, 2393, 2391} \[ \frac{b^2 \text{PolyLog}\left (2,\frac{1}{2} \left (1-i c x^2\right )\right )}{8 c^2}+\frac{b^2 \text{PolyLog}\left (2,\frac{1}{2} \left (1+i c x^2\right )\right )}{8 c^2}-\frac{\left (1-i c x^2\right )^2 \left (2 a+i b \log \left (1-i c x^2\right )\right )^2}{16 c^2}+\frac{\left (1-i c x^2\right ) \left (2 a+i b \log \left (1-i c x^2\right )\right )^2}{8 c^2}+\frac{i b \left (1-i c x^2\right )^2 \left (2 a+i b \log \left (1-i c x^2\right )\right )}{16 c^2}-\frac{b \log \left (\frac{1}{2} \left (1+i c x^2\right )\right ) \left (2 i a-b \log \left (1-i c x^2\right )\right )}{8 c^2}-\frac{3 a b x^2}{4 c}+\frac{1}{16} b x^4 \left (2 i a-b \log \left (1-i c x^2\right )\right )-\frac{1}{8} b x^4 \log \left (1+i c x^2\right ) \left (2 i a-b \log \left (1-i c x^2\right )\right )+\frac{b^2 \left (1-i c x^2\right )^2}{32 c^2}+\frac{b^2 \left (1+i c x^2\right )^2}{32 c^2}+\frac{b^2 \left (1+i c x^2\right )^2 \log ^2\left (1+i c x^2\right )}{16 c^2}-\frac{b^2 \left (1+i c x^2\right ) \log ^2\left (1+i c x^2\right )}{8 c^2}-\frac{b^2 \log \left (-c x^2+i\right )}{16 c^2}+\frac{3 b^2 \left (1-i c x^2\right ) \log \left (1-i c x^2\right )}{8 c^2}-\frac{b^2 \left (1+i c x^2\right )^2 \log \left (1+i c x^2\right )}{16 c^2}+\frac{3 b^2 \left (1+i c x^2\right ) \log \left (1+i c x^2\right )}{8 c^2}+\frac{b^2 \log \left (\frac{1}{2} \left (1-i c x^2\right )\right ) \log \left (1+i c x^2\right )}{8 c^2}-\frac{b^2 \log \left (c x^2+i\right )}{16 c^2}-\frac{1}{16} b^2 x^4 \log \left (1+i c x^2\right )+\frac{b^2 x^4}{16} \]
Warning: Unable to verify antiderivative.
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Rule 5035
Rule 2454
Rule 2401
Rule 2389
Rule 2296
Rule 2295
Rule 2390
Rule 2305
Rule 2304
Rule 2395
Rule 43
Rule 2439
Rule 2416
Rule 2394
Rule 2393
Rule 2391
Rubi steps
\begin{align*} \int x^3 \left (a+b \tan ^{-1}\left (c x^2\right )\right )^2 \, dx &=\int \left (\frac{1}{4} x^3 \left (2 a+i b \log \left (1-i c x^2\right )\right )^2+\frac{1}{2} b x^3 \left (-2 i a+b \log \left (1-i c x^2\right )\right ) \log \left (1+i c x^2\right )-\frac{1}{4} b^2 x^3 \log ^2\left (1+i c x^2\right )\right ) \, dx\\ &=\frac{1}{4} \int x^3 \left (2 a+i b \log \left (1-i c x^2\right )\right )^2 \, dx+\frac{1}{2} b \int x^3 \left (-2 i a+b \log \left (1-i c x^2\right )\right ) \log \left (1+i c x^2\right ) \, dx-\frac{1}{4} b^2 \int x^3 \log ^2\left (1+i c x^2\right ) \, dx\\ &=\frac{1}{8} \operatorname{Subst}\left (\int x (2 a+i b \log (1-i c x))^2 \, dx,x,x^2\right )+\frac{1}{4} b \operatorname{Subst}\left (\int x (-2 i a+b \log (1-i c x)) \log (1+i c x) \, dx,x,x^2\right )-\frac{1}{8} b^2 \operatorname{Subst}\left (\int x \log ^2(1+i c x) \, dx,x,x^2\right )\\ &=-\frac{1}{8} b x^4 \left (2 i a-b \log \left (1-i c x^2\right )\right ) \log \left (1+i c x^2\right )+\frac{1}{8} \operatorname{Subst}\left (\int \left (-\frac{i (2 a+i b \log (1-i c x))^2}{c}+\frac{i (1-i c x) (2 a+i b \log (1-i c x))^2}{c}\right ) \, dx,x,x^2\right )-\frac{1}{8} b^2 \operatorname{Subst}\left (\int \left (\frac{i \log ^2(1+i c x)}{c}-\frac{i (1+i c x) \log ^2(1+i c x)}{c}\right ) \, dx,x,x^2\right )-\frac{1}{8} (i b c) \operatorname{Subst}\left (\int \frac{x^2 (-2 i a+b \log (1-i c x))}{1+i c x} \, dx,x,x^2\right )+\frac{1}{8} \left (i b^2 c\right ) \operatorname{Subst}\left (\int \frac{x^2 \log (1+i c x)}{1-i c x} \, dx,x,x^2\right )\\ &=-\frac{1}{8} b x^4 \left (2 i a-b \log \left (1-i c x^2\right )\right ) \log \left (1+i c x^2\right )-\frac{i \operatorname{Subst}\left (\int (2 a+i b \log (1-i c x))^2 \, dx,x,x^2\right )}{8 c}+\frac{i \operatorname{Subst}\left (\int (1-i c x) (2 a+i b \log (1-i c x))^2 \, dx,x,x^2\right )}{8 c}-\frac{\left (i b^2\right ) \operatorname{Subst}\left (\int \log ^2(1+i c x) \, dx,x,x^2\right )}{8 c}+\frac{\left (i b^2\right ) \operatorname{Subst}\left (\int (1+i c x) \log ^2(1+i c x) \, dx,x,x^2\right )}{8 c}-\frac{1}{8} (i b c) \operatorname{Subst}\left (\int \left (\frac{-2 i a+b \log (1-i c x)}{c^2}-\frac{i x (-2 i a+b \log (1-i c x))}{c}+\frac{i (-2 i a+b \log (1-i c x))}{c^2 (-i+c x)}\right ) \, dx,x,x^2\right )+\frac{1}{8} \left (i b^2 c\right ) \operatorname{Subst}\left (\int \left (\frac{\log (1+i c x)}{c^2}+\frac{i x \log (1+i c x)}{c}-\frac{i \log (1+i c x)}{c^2 (i+c x)}\right ) \, dx,x,x^2\right )\\ &=-\frac{1}{8} b x^4 \left (2 i a-b \log \left (1-i c x^2\right )\right ) \log \left (1+i c x^2\right )-\frac{1}{8} b \operatorname{Subst}\left (\int x (-2 i a+b \log (1-i c x)) \, dx,x,x^2\right )-\frac{1}{8} b^2 \operatorname{Subst}\left (\int x \log (1+i c x) \, dx,x,x^2\right )+\frac{\operatorname{Subst}\left (\int (2 a+i b \log (x))^2 \, dx,x,1-i c x^2\right )}{8 c^2}-\frac{\operatorname{Subst}\left (\int x (2 a+i b \log (x))^2 \, dx,x,1-i c x^2\right )}{8 c^2}-\frac{b^2 \operatorname{Subst}\left (\int \log ^2(x) \, dx,x,1+i c x^2\right )}{8 c^2}+\frac{b^2 \operatorname{Subst}\left (\int x \log ^2(x) \, dx,x,1+i c x^2\right )}{8 c^2}-\frac{(i b) \operatorname{Subst}\left (\int (-2 i a+b \log (1-i c x)) \, dx,x,x^2\right )}{8 c}+\frac{b \operatorname{Subst}\left (\int \frac{-2 i a+b \log (1-i c x)}{-i+c x} \, dx,x,x^2\right )}{8 c}+\frac{\left (i b^2\right ) \operatorname{Subst}\left (\int \log (1+i c x) \, dx,x,x^2\right )}{8 c}+\frac{b^2 \operatorname{Subst}\left (\int \frac{\log (1+i c x)}{i+c x} \, dx,x,x^2\right )}{8 c}\\ &=-\frac{a b x^2}{4 c}+\frac{1}{16} b x^4 \left (2 i a-b \log \left (1-i c x^2\right )\right )+\frac{\left (1-i c x^2\right ) \left (2 a+i b \log \left (1-i c x^2\right )\right )^2}{8 c^2}-\frac{\left (1-i c x^2\right )^2 \left (2 a+i b \log \left (1-i c x^2\right )\right )^2}{16 c^2}-\frac{b \left (2 i a-b \log \left (1-i c x^2\right )\right ) \log \left (\frac{1}{2} \left (1+i c x^2\right )\right )}{8 c^2}-\frac{1}{16} b^2 x^4 \log \left (1+i c x^2\right )+\frac{b^2 \log \left (\frac{1}{2} \left (1-i c x^2\right )\right ) \log \left (1+i c x^2\right )}{8 c^2}-\frac{1}{8} b x^4 \left (2 i a-b \log \left (1-i c x^2\right )\right ) \log \left (1+i c x^2\right )-\frac{b^2 \left (1+i c x^2\right ) \log ^2\left (1+i c x^2\right )}{8 c^2}+\frac{b^2 \left (1+i c x^2\right )^2 \log ^2\left (1+i c x^2\right )}{16 c^2}+\frac{(i b) \operatorname{Subst}\left (\int x (2 a+i b \log (x)) \, dx,x,1-i c x^2\right )}{8 c^2}-\frac{(i b) \operatorname{Subst}\left (\int (2 a+i b \log (x)) \, dx,x,1-i c x^2\right )}{4 c^2}+\frac{b^2 \operatorname{Subst}\left (\int \log (x) \, dx,x,1+i c x^2\right )}{8 c^2}-\frac{b^2 \operatorname{Subst}\left (\int x \log (x) \, dx,x,1+i c x^2\right )}{8 c^2}+\frac{b^2 \operatorname{Subst}\left (\int \log (x) \, dx,x,1+i c x^2\right )}{4 c^2}-\frac{\left (i b^2\right ) \operatorname{Subst}\left (\int \log (1-i c x) \, dx,x,x^2\right )}{8 c}+\frac{\left (i b^2\right ) \operatorname{Subst}\left (\int \frac{\log \left (\frac{1}{2} i (-i+c x)\right )}{1-i c x} \, dx,x,x^2\right )}{8 c}-\frac{\left (i b^2\right ) \operatorname{Subst}\left (\int \frac{\log \left (-\frac{1}{2} i (i+c x)\right )}{1+i c x} \, dx,x,x^2\right )}{8 c}-\frac{1}{16} \left (i b^2 c\right ) \operatorname{Subst}\left (\int \frac{x^2}{1-i c x} \, dx,x,x^2\right )+\frac{1}{16} \left (i b^2 c\right ) \operatorname{Subst}\left (\int \frac{x^2}{1+i c x} \, dx,x,x^2\right )\\ &=-\frac{3 a b x^2}{4 c}-\frac{3 i b^2 x^2}{8 c}+\frac{b^2 \left (1-i c x^2\right )^2}{32 c^2}+\frac{b^2 \left (1+i c x^2\right )^2}{32 c^2}+\frac{1}{16} b x^4 \left (2 i a-b \log \left (1-i c x^2\right )\right )+\frac{i b \left (1-i c x^2\right )^2 \left (2 a+i b \log \left (1-i c x^2\right )\right )}{16 c^2}+\frac{\left (1-i c x^2\right ) \left (2 a+i b \log \left (1-i c x^2\right )\right )^2}{8 c^2}-\frac{\left (1-i c x^2\right )^2 \left (2 a+i b \log \left (1-i c x^2\right )\right )^2}{16 c^2}-\frac{b \left (2 i a-b \log \left (1-i c x^2\right )\right ) \log \left (\frac{1}{2} \left (1+i c x^2\right )\right )}{8 c^2}-\frac{1}{16} b^2 x^4 \log \left (1+i c x^2\right )+\frac{3 b^2 \left (1+i c x^2\right ) \log \left (1+i c x^2\right )}{8 c^2}-\frac{b^2 \left (1+i c x^2\right )^2 \log \left (1+i c x^2\right )}{16 c^2}+\frac{b^2 \log \left (\frac{1}{2} \left (1-i c x^2\right )\right ) \log \left (1+i c x^2\right )}{8 c^2}-\frac{1}{8} b x^4 \left (2 i a-b \log \left (1-i c x^2\right )\right ) \log \left (1+i c x^2\right )-\frac{b^2 \left (1+i c x^2\right ) \log ^2\left (1+i c x^2\right )}{8 c^2}+\frac{b^2 \left (1+i c x^2\right )^2 \log ^2\left (1+i c x^2\right )}{16 c^2}-\frac{b^2 \operatorname{Subst}\left (\int \frac{\log \left (1-\frac{x}{2}\right )}{x} \, dx,x,1-i c x^2\right )}{8 c^2}-\frac{b^2 \operatorname{Subst}\left (\int \frac{\log \left (1-\frac{x}{2}\right )}{x} \, dx,x,1+i c x^2\right )}{8 c^2}+\frac{b^2 \operatorname{Subst}\left (\int \log (x) \, dx,x,1-i c x^2\right )}{8 c^2}+\frac{b^2 \operatorname{Subst}\left (\int \log (x) \, dx,x,1-i c x^2\right )}{4 c^2}+\frac{1}{16} \left (i b^2 c\right ) \operatorname{Subst}\left (\int \left (\frac{1}{c^2}-\frac{i x}{c}+\frac{i}{c^2 (-i+c x)}\right ) \, dx,x,x^2\right )-\frac{1}{16} \left (i b^2 c\right ) \operatorname{Subst}\left (\int \left (\frac{1}{c^2}+\frac{i x}{c}-\frac{i}{c^2 (i+c x)}\right ) \, dx,x,x^2\right )\\ &=-\frac{3 a b x^2}{4 c}+\frac{b^2 x^4}{16}+\frac{b^2 \left (1-i c x^2\right )^2}{32 c^2}+\frac{b^2 \left (1+i c x^2\right )^2}{32 c^2}-\frac{b^2 \log \left (i-c x^2\right )}{16 c^2}+\frac{3 b^2 \left (1-i c x^2\right ) \log \left (1-i c x^2\right )}{8 c^2}+\frac{1}{16} b x^4 \left (2 i a-b \log \left (1-i c x^2\right )\right )+\frac{i b \left (1-i c x^2\right )^2 \left (2 a+i b \log \left (1-i c x^2\right )\right )}{16 c^2}+\frac{\left (1-i c x^2\right ) \left (2 a+i b \log \left (1-i c x^2\right )\right )^2}{8 c^2}-\frac{\left (1-i c x^2\right )^2 \left (2 a+i b \log \left (1-i c x^2\right )\right )^2}{16 c^2}-\frac{b \left (2 i a-b \log \left (1-i c x^2\right )\right ) \log \left (\frac{1}{2} \left (1+i c x^2\right )\right )}{8 c^2}-\frac{1}{16} b^2 x^4 \log \left (1+i c x^2\right )+\frac{3 b^2 \left (1+i c x^2\right ) \log \left (1+i c x^2\right )}{8 c^2}-\frac{b^2 \left (1+i c x^2\right )^2 \log \left (1+i c x^2\right )}{16 c^2}+\frac{b^2 \log \left (\frac{1}{2} \left (1-i c x^2\right )\right ) \log \left (1+i c x^2\right )}{8 c^2}-\frac{1}{8} b x^4 \left (2 i a-b \log \left (1-i c x^2\right )\right ) \log \left (1+i c x^2\right )-\frac{b^2 \left (1+i c x^2\right ) \log ^2\left (1+i c x^2\right )}{8 c^2}+\frac{b^2 \left (1+i c x^2\right )^2 \log ^2\left (1+i c x^2\right )}{16 c^2}-\frac{b^2 \log \left (i+c x^2\right )}{16 c^2}+\frac{b^2 \text{Li}_2\left (\frac{1}{2} \left (1-i c x^2\right )\right )}{8 c^2}+\frac{b^2 \text{Li}_2\left (\frac{1}{2} \left (1+i c x^2\right )\right )}{8 c^2}\\ \end{align*}
Mathematica [A] time = 0.0640039, size = 85, normalized size = 0.94 \[ \frac{2 b \tan ^{-1}\left (c x^2\right ) \left (a c^2 x^4+a-b c x^2\right )+a c x^2 \left (a c x^2-2 b\right )+b^2 \log \left (c^2 x^4+1\right )+b^2 \left (c^2 x^4+1\right ) \tan ^{-1}\left (c x^2\right )^2}{4 c^2} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.033, size = 113, normalized size = 1.3 \begin{align*}{\frac{{a}^{2}{x}^{4}}{4}}+{\frac{{b}^{2}{x}^{4} \left ( \arctan \left ( c{x}^{2} \right ) \right ) ^{2}}{4}}-{\frac{{b}^{2}{x}^{2}\arctan \left ( c{x}^{2} \right ) }{2\,c}}+{\frac{{b}^{2} \left ( \arctan \left ( c{x}^{2} \right ) \right ) ^{2}}{4\,{c}^{2}}}+{\frac{{b}^{2}\ln \left ({c}^{2}{x}^{4}+1 \right ) }{4\,{c}^{2}}}+{\frac{ab{x}^{4}\arctan \left ( c{x}^{2} \right ) }{2}}-{\frac{ab{x}^{2}}{2\,c}}+{\frac{ab\arctan \left ( c{x}^{2} \right ) }{2\,{c}^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.75226, size = 170, normalized size = 1.89 \begin{align*} \frac{1}{4} \, b^{2} x^{4} \arctan \left (c x^{2}\right )^{2} + \frac{1}{4} \, a^{2} x^{4} + \frac{1}{2} \,{\left (x^{4} \arctan \left (c x^{2}\right ) - c{\left (\frac{x^{2}}{c^{2}} - \frac{\arctan \left (c x^{2}\right )}{c^{3}}\right )}\right )} a b - \frac{1}{4} \,{\left (2 \, c{\left (\frac{x^{2}}{c^{2}} - \frac{\arctan \left (c x^{2}\right )}{c^{3}}\right )} \arctan \left (c x^{2}\right ) + \frac{\arctan \left (c x^{2}\right )^{2} - \log \left (4 \, c^{5} x^{4} + 4 \, c^{3}\right )}{c^{2}}\right )} b^{2} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.77326, size = 227, normalized size = 2.52 \begin{align*} \frac{a^{2} c^{2} x^{4} - 2 \, a b c x^{2} +{\left (b^{2} c^{2} x^{4} + b^{2}\right )} \arctan \left (c x^{2}\right )^{2} - 2 \, a b \arctan \left (\frac{1}{c x^{2}}\right ) + b^{2} \log \left (c^{2} x^{4} + 1\right ) + 2 \,{\left (a b c^{2} x^{4} - b^{2} c x^{2}\right )} \arctan \left (c x^{2}\right )}{4 \, c^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 63.5517, size = 529, normalized size = 5.88 \begin{align*} \begin{cases} \frac{a^{2} x^{4}}{4} & \text{for}\: c = 0 \\\frac{x^{4} \left (a - \infty i b\right )^{2}}{4} & \text{for}\: c = - \frac{i}{x^{2}} \\\frac{x^{4} \left (a + \infty i b\right )^{2}}{4} & \text{for}\: c = \frac{i}{x^{2}} \\\frac{a^{2} c^{4} x^{8}}{4 c^{4} x^{4} + 4 c^{2}} - \frac{a^{2}}{4 c^{4} x^{4} + 4 c^{2}} + \frac{2 a b c^{4} x^{8} \operatorname{atan}{\left (c x^{2} \right )}}{4 c^{4} x^{4} + 4 c^{2}} - \frac{2 a b c^{3} x^{6}}{4 c^{4} x^{4} + 4 c^{2}} + \frac{4 a b c^{2} x^{4} \operatorname{atan}{\left (c x^{2} \right )}}{4 c^{4} x^{4} + 4 c^{2}} - \frac{2 a b c x^{2}}{4 c^{4} x^{4} + 4 c^{2}} + \frac{2 a b \operatorname{atan}{\left (c x^{2} \right )}}{4 c^{4} x^{4} + 4 c^{2}} + \frac{2 i b^{2} c^{5} x^{4} \left (\frac{1}{c^{2}}\right )^{\frac{3}{2}} \operatorname{atan}{\left (c x^{2} \right )}}{4 c^{4} x^{4} + 4 c^{2}} + \frac{b^{2} c^{4} x^{8} \operatorname{atan}^{2}{\left (c x^{2} \right )}}{4 c^{4} x^{4} + 4 c^{2}} - \frac{2 b^{2} c^{3} x^{6} \operatorname{atan}{\left (c x^{2} \right )}}{4 c^{4} x^{4} + 4 c^{2}} + \frac{2 b^{2} c^{2} x^{4} \log{\left (x^{2} + i \sqrt{\frac{1}{c^{2}}} \right )}}{4 c^{4} x^{4} + 4 c^{2}} + \frac{2 b^{2} c^{2} x^{4} \operatorname{atan}^{2}{\left (c x^{2} \right )}}{4 c^{4} x^{4} + 4 c^{2}} - \frac{2 b^{2} c x^{2} \operatorname{atan}{\left (c x^{2} \right )}}{4 c^{4} x^{4} + 4 c^{2}} + \frac{2 i b^{2} c \sqrt{\frac{1}{c^{2}}} \operatorname{atan}{\left (c x^{2} \right )}}{4 c^{4} x^{4} + 4 c^{2}} + \frac{2 b^{2} \log{\left (x^{2} + i \sqrt{\frac{1}{c^{2}}} \right )}}{4 c^{4} x^{4} + 4 c^{2}} + \frac{b^{2} \operatorname{atan}^{2}{\left (c x^{2} \right )}}{4 c^{4} x^{4} + 4 c^{2}} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.19708, size = 135, normalized size = 1.5 \begin{align*} \frac{a^{2} c x^{4} + \frac{2 \,{\left (c^{2} x^{4} \arctan \left (c x^{2}\right ) - c x^{2} + \arctan \left (c x^{2}\right )\right )} a b}{c} + \frac{{\left (c^{2} x^{4} \arctan \left (c x^{2}\right )^{2} - 2 \, c x^{2} \arctan \left (c x^{2}\right ) + \arctan \left (c x^{2}\right )^{2} + \log \left (c^{2} x^{4} + 1\right )\right )} b^{2}}{c}}{4 \, c} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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